(x+4)+(x^2-4x-2)+(1-x^2)=0

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Solution for (x+4)+(x^2-4x-2)+(1-x^2)=0 equation:


Simplifying
(x + 4) + (x2 + -4x + -2) + (1 + -1x2) = 0

Reorder the terms:
(4 + x) + (x2 + -4x + -2) + (1 + -1x2) = 0

Remove parenthesis around (4 + x)
4 + x + (x2 + -4x + -2) + (1 + -1x2) = 0

Reorder the terms:
4 + x + (-2 + -4x + x2) + (1 + -1x2) = 0

Remove parenthesis around (-2 + -4x + x2)
4 + x + -2 + -4x + x2 + (1 + -1x2) = 0

Remove parenthesis around (1 + -1x2)
4 + x + -2 + -4x + x2 + 1 + -1x2 = 0

Reorder the terms:
4 + -2 + 1 + x + -4x + x2 + -1x2 = 0

Combine like terms: 4 + -2 = 2
2 + 1 + x + -4x + x2 + -1x2 = 0

Combine like terms: 2 + 1 = 3
3 + x + -4x + x2 + -1x2 = 0

Combine like terms: x + -4x = -3x
3 + -3x + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
3 + -3x + 0 = 0
3 + -3x = 0

Solving
3 + -3x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -3x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -3x = 0 + -3
-3x = 0 + -3

Combine like terms: 0 + -3 = -3
-3x = -3

Divide each side by '-3'.
x = 1

Simplifying
x = 1

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